6b^2+5b-35=3b

Solution for 6b^2+5b-35=3b equation:

6b^2+5b-35=3b

We move all terms to the left:

6b^2+5b-35-(3b)=0

We add all the numbers together, and all the variables

6b^2+2b-35=0

a = 6; b = 2; c = -35;
Δ = b2-4ac
Δ = 22-4·6·(-35)
Δ = 844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{844}=\sqrt{4*211}=\sqrt{4}*\sqrt{211}=2\sqrt{211}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{211}}{2*6}=\frac{-2-2\sqrt{211}}{12}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{211}}{2*6}=\frac{-2+2\sqrt{211}}{12}
$